MySQL不使用order by實現(xiàn)排名的三種思路總結(jié)
假定業(yè)務(wù):
查看在職員工的薪資的第二名的員工信息
創(chuàng)建數(shù)據(jù)庫
drop database if exists emps;create database emps;use emps;create table employees( empId int primary key,-- 員工編號 gender char(1) NOT NULL, -- 員工性別hire_date date NOT NULL -- 員工入職時間 );create table salaries( empId int primary key, salary double -- 員工薪資 ); INSERT INTO employees VALUES(10001,’M’,’1986-06-26’);INSERT INTO employees VALUES(10002,’F’,’1985-11-21’);INSERT INTO employees VALUES(10003,’M’,’1986-08-28’);INSERT INTO employees VALUES(10004,’M’,’1986-12-01’);INSERT INTO salaries VALUES(10001,88958);INSERT INTO salaries VALUES(10002,72527);INSERT INTO salaries VALUES(10003,43311);INSERT INTO salaries VALUES(10004,74057);
題解思路
1、(基礎(chǔ)解法)
先查出salaries表中最高薪資,再以此為條件查出第二高的工資
查詢語句如下:
selectE.empId,E.gender,E.hire_date,S.salaryfromemployees E join salaries S on E.empId = S.empIdwhereS.salary=( select max(salary)from salaries where salary<(select max(salary) from salaries) );-- ---------------查詢結(jié)果------------ --+-------+--------+------------+--------+| empId | gender | hire_date | salary |+-------+--------+------------+--------+| 10004 | M | 1986-12-01 | 74057 |+-------+--------+------------+--------+
2、(自聯(lián)結(jié)查詢)
先對salaries進行自聯(lián)結(jié)查詢,當(dāng)s1<=s2鏈接并以s1.salary分組,此時count的值,即薪資比他高的人數(shù),用having篩選count=2 的人,就可以得到第二高的薪資了;
查詢語句如下:
selectE.empId,E.gender,E.hire_date,S.salaryfromemployees E join salaries S on E.empId = S.empIdwhere S.salary=( select s1.salary from salaries s1 join salaries s2 on s1.salary <= s2.salary group by s1.salaryhaving count(distinct s2.salary) = 2 );-- ---------------查詢結(jié)果------------ --+-------+--------+------------+--------+| empId | gender | hire_date | salary |+-------+--------+------------+--------+| 10004 | M | 1986-12-01 | 74057 |+-------+--------+------------+--------+
3、(自聯(lián)結(jié)查詢優(yōu)化版)
原理和2相同,但是代碼精簡了很多,上面兩種是為了引出最后這種方法,在很多時候group by和order by都有其局限性,對于俺們初學(xué)者掌握這種實用性較廣的思路,還是很有意義的。
selectE.empId,E.gender,E.hire_date,S.salaryfromemployees E join salaries S on S.empId =E.empIdwhere (select count(1) from salaries where salary>=S.salary)=2;-- ---------------查詢結(jié)果------------ --+-------+--------+------------+--------+| empId | gender | hire_date | salary |+-------+--------+------------+--------+| 10004 | M | 1986-12-01 | 74057 |+-------+--------+------------+--------+
初淺總結(jié),如有錯誤,還望指正。
總結(jié)
到此這篇關(guān)于MySQL不使用order by實現(xiàn)排名的三種思路的文章就介紹到這了,更多相關(guān)MySQL不用order by排名內(nèi)容請搜索好吧啦網(wǎng)以前的文章或繼續(xù)瀏覽下面的相關(guān)文章希望大家以后多多支持好吧啦網(wǎng)!
相關(guān)文章:
1. Mysql故障排除:Starting MySQL. ERROR! Manager of pid-file quit without updating file2. Access數(shù)據(jù)庫安全的幾個問題3. MySQL中 concat函數(shù)的使用4. oracle觸發(fā)器介紹5. Windows下在DOS用mysql命令行導(dǎo)入.sql文件6. Delphi中的Access技巧集7. mysql數(shù)據(jù)庫中最常用的時間轉(zhuǎn)換函數(shù)的用法8. MySQL入門教程7 —— 常用數(shù)據(jù)庫查詢的示例9. 啟動MYSQL出錯 Manager of pid-file quit without updating file.10. 數(shù)據(jù)庫相關(guān)的幾個技能:ACCESS轉(zhuǎn)SQL
