問題描述

links = sel.xpath(’//i[contains(@title,'置頂')]/following-sibling::a/@href’).extract()

報錯：ValueError: All strings must be XML compatible: Unicode or ASCII, no NULL bytes or control characters

問題解答

參見文章：解決Scrapy中xpath用到中文報錯問題

方法一：將整個xpath語句轉(zhuǎn)成Unicode

links = sel.xpath(u’//i[contains(@title,'置頂')]/following-sibling::a/@href’).extract()

方法二：xpath語句用已轉(zhuǎn)成Unicode的title變量

title = u'置頂'links = sel.xpath(’//i[contains(@title,'%s')]/following-sibling::a/@href’ %(title)).extract()

方法三：直接用xpath中變量語法($符號加變量名)$title, 傳參title即可

links = sel.xpath(’//i[contains(@title,$title)]/following-sibling::a/@href’,).extract()回答2：

整個字符串前加個u試試